If a RADAR transmitter has a pulse repetition frequency (PRF) of 900 Hz and a pulse width of 0.5 microseconds, what is its average power output?

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Multiple Choice

If a RADAR transmitter has a pulse repetition frequency (PRF) of 900 Hz and a pulse width of 0.5 microseconds, what is its average power output?

Explanation:
To determine the average power output of the RADAR transmitter, you can use the formula relating average power to pulse repetition frequency (PRF), pulse width, and peak power. The average power output (P_avg) can be calculated using the equation: \[ P_{avg} = P_{peak} \times \text{Duty Cycle} \] The duty cycle is defined as the product of the pulse width (in seconds) and the PRF. The first step is to convert the pulse width from microseconds to seconds: \[ \text{Pulse width} = 0.5 \, \mu s = 0.5 \times 10^{-6} \, s = 0.0000005 \, s \] Next, using the PRF of 900 Hz: \[ \text{Duty Cycle} = \text{Pulse Width} \times \text{PRF} \] \[ \text{Duty Cycle} = 0.5 \times 10^{-6} s \times 900 \, Hz = 0.00045 \] Now, let's relate this to the average power output. The average power can be related to the peak power and is also influenced by the duty cycle.

To determine the average power output of the RADAR transmitter, you can use the formula relating average power to pulse repetition frequency (PRF), pulse width, and peak power. The average power output (P_avg) can be calculated using the equation:

[ P_{avg} = P_{peak} \times \text{Duty Cycle} ]

The duty cycle is defined as the product of the pulse width (in seconds) and the PRF. The first step is to convert the pulse width from microseconds to seconds:

[ \text{Pulse width} = 0.5 , \mu s = 0.5 \times 10^{-6} , s = 0.0000005 , s ]

Next, using the PRF of 900 Hz:

[ \text{Duty Cycle} = \text{Pulse Width} \times \text{PRF} ]

[ \text{Duty Cycle} = 0.5 \times 10^{-6} s \times 900 , Hz = 0.00045 ]

Now, let's relate this to the average power output. The average power can be related to the peak power and is also influenced by the duty cycle.

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